Question

in the following figure triangle abc a equilateral triangle. 4 radius of small is 2 cm. find 1.radius of big circle​

Answer 1

Answer:

⇒  Here, AB=BC=AC=12cm

⇒  Let OP=OR=OQ=r

⇒ We have O as the incenter and OP,OQ and OR are equal.

⇒  ar(△ABC)=ar(△OAB)+ar(△OBC)+ar(△OCA)

43×(side)2=(21×OP×AB)+(21×OQ×BC)+(21×OR×AC)

⇒  43×(12)2=(21×r×12)+(21×r×12)+(21×r×12)

⇒  43×(12)