Question

In the following figure triangle abc is an equilateral triangle. Find angle x

Answer 1

Answer:

x=30

Step-by-step explanation:

∆abc is equilateral triangle.

<abd=120.

in ∆abd

x + 120 +30 =180

x=30.

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Answer 2

Value is $\bf x = {30}^{ \circ}$

Given:

• A figure.
• ∆ABC is an equilateral triangle.

To find:

• Find the value of x.

Solution:

Concept to be used:

• Use property of equilateral triangle.
• Apply concept of linear pair.
• Apply angle sum property of triangle.

Step 1:

According to the property of equilateral triangle.

$\bf \angle A=\angle B=\angle C = 60 ^{ \circ}$

Step 2:

Find the $\angle ABD$.

As the angles $\angle ABD \: and \: \angle B$ form linear pair.

So,

$\angle ABD + \angle B = {180}^{ \circ}$

or

$\angle ABD = {180}^{ \circ} - {60}^{ \circ}$

or

$\bf \angle ABD = {120}^{ \circ}$

Step 3:

Apply angle sum property of triangle.

In ∆ABD.

$x + {30}^{ \circ} + {120}^{ \circ} = {180}^{ \circ}$

or

$x = {180}^{ \circ} - {150}^{ \circ}$

or

$x = {30}^{ \circ}$

Thus,

Value of x is 30°.

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