Question

in the following figure triangle ABC is right angled at a q and R are points and line BC and P is a point such that QP is parallel to AC and RP find angle p​

Answer 1

Answer:

90°

Step-by-step explanation:

Given that QP || AC,

=> Angle PQC = angle QCA (alternate angles)

Given that RP || AB,

=> Angle PRQ = Angle QBA

So, ∆ABC is similar to ∆PRQ (AA)

=> Angle A = Angle P (correspond angles of similar triangles)

But, Angle A is 90° => Angle P = 90°.