In the following figures a pair of parallel lines are cut by a transversal.Find the size of each lettered angle.
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8
Answer:
q = 180 - 62 (linear pair)
= 118 degree
p = 62 degree (vertically opposite angles)
r = 180-p = 118 degree (because they form co-interior angles and there sum = 180 degree)
s = 180-r = 62 degree (linear pair)
Answered by
4
Answer:
p=62(v.o.a)
q forms a linear pair with p
∴q=180-62=118
r and q forms a pair of alternate interior angles
r=q=118
p and s forms a pair of corresponding angles therefore they should be equal
p=s=62
hence....
p=62
q=118
r=118
s=62
hope this helps....... :p
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