Question

In the following figures a pair of parallel lines are cut by a transversal.Find the size of each lettered angle.

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Answer 1

Answer:

q = 180 - 62 (linear pair)

   = 118 degree

p = 62 degree (vertically opposite angles)

r = 180-p = 118 degree (because they form co-interior angles and there sum = 180 degree)

s = 180-r = 62 degree (linear pair)

Answer 2

Answer:

p=62(v.o.a)

q forms a linear pair with p

∴q=180-62=118

r and q forms a pair of alternate interior angles

     r=q=118

p and s forms a pair of corresponding angles therefore they should be equal

p=s=62

hence....

p=62

q=118

r=118

s=62

hope this helps.......  :p

Step-by-step explanation: