IN THE FOLLOWING FIGURES, FIND THE AREA OF THE SHADED PORTIONS:
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. WHOEVER WILL ANSWER ME CORRECTLY I WILL MARK HIM/HER AS BRILLIANT ✨✨✨✨
Answers
Topic :-
Mensuration
To Find :-
Area of shaded region.
Steps :-
- Calculate area of square.
- Calculate area of remaining three triangles.
- Subtract area of 3 triangles from square.
Solution :-
Calculating area of square
Area of square = ( Side )²
Given side of square = 20 cm
Area of square = ( 20 cm )²
Area of square = 400 cm²
Calculating area of 3 triangles :-
Area of Triangle = ( Base × Height ) / 2
Area of ∆TSU,
- Base = 10 cm
- Height = 10 cm
Area of ∆TSU = [ ( 10 × 10 ) / 2 ] cm²
Area of ∆TSU = 50 cm²
Area of ∆UQR,
- Base = 10 cm
- Height = 20 cm
Area of ∆UQR = [ ( 10 × 20 ) / 2 ] cm²
Area of ∆UQR = 100 cm²
Area of ∆PTQ,
- Base = 10 cm
- Height = 20 cm
Area of ∆PTQ = [ ( 10 × 20 ) / 2 ] cm²
Area of ∆PTQ = 100 cm²
Now,
Area of shaded region = Area of square - Sum of area of 3 triangles
Area of shaded region = 400 cm² - ( 50 + 100 + 100 ) cm²
Area of shaded region = 400 cm² - 250 cm²
Area of shaded region = 150 cm²
Answer :-
So, area of shaded region = 150 cm²
Note :- You may also calculate area of shaded triangle with the help of Heron's Formula after applying Pythagoras Theorem in remaining 3 triangles.
We have to find out area of shaded portion. Which means we have to find out area of ∆QTU.
PQRS is a square of length 20 cm.
➝ area of ∆QTU = Area of square PQRS - [ Area of ∆TSU + Area of ∆PQT + Area of ∆QUR ]
➡️First we will find area of square PQRS :-
=> Area of square PQRS = side× side
= 20×20
= 400 cm²
➡️ Now , we will find area of ∆TSU :-
base = 10 cm
height = 10 cm
Area =( 1/2)× (10)×(10)
= 5 × 10
= 50 cm²
➡️ Now , we will find area of ∆PQT :-
base = 10 cm
height = 20 cm
Area =( 1/2)× (10)×(20)
= 5 × 20
= 100 cm²
➡️ Now , we will find area of ∆QUR :-
base = 10 cm
height = 20 cm
Area =( 1/2)× (10)×(20)
= 5 × 20
= 100 cm²
➝ area of ∆QTU = 400 - [50 + 100 +100 ]
➝ area of ∆QTU = 400 - 250
➝ area of ∆QTU = 150 cm²
Therefore, area of shaded region = 150 cm²