Question

In the following figures, find the area of the shaded portions:

a) Find the perimeter of ABCD.

b) Find the area of triangle BCE.

c) Find the area of triangle AEF.

d) Find the length of CE.​

Answer 1

Answer:

mark as a brainliest

Step-by-step explanation:

Correct option is

A

119.8 cm  

2

;11.98 cm

Given, AB=12 cm, BC=10 cm

BD is the diagonal of parallelogram ABCD.

Also BD=16 cm

We know, △ABD≅△DCB     [S−S−S Congruence]

Also, area of parallelogram ABCD = Area of △ABD + Area of △DCB

                                            = 2 × Area of △ABD

                                            = 2  

s(s−12)(s−10)(s−16)

​  

 

s=  

2

12+10+16

​  

 

  = 19

Therefore, area of parallelogram ABCD= 2  

19(19−12)(19−10)(19−16)

​  

 

                                           = 2  

3591

​  

 

                                           = 2(59.92)

                                           = 119.8 cm  

2

 

Also, h is the distance of the two shorter sides.

We know, area of parallelogram = base×height

                                   = BC×h

Therefore, h=  

BC

Area of parallelogram ABCD

​  

 

⇒h=  

10

119.8

​  

 

⇒h=11.98 cm