in the following figures ,find the area of the shaded regions:
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i). ABCD is a rectangle in which
Length = 18 cm
Breadth b= 10 cm
Area = 18 × 10 = 180cm²
DE = 10 cm
EC = 18-10 = 8cm
Now area of ∆BCE = 1/2×BC×EC
= 1/2×10×8 = 40cm²
And area of ∆FDE = 1/2×DC×DF
= 1/2×10×6=30cm²
Area of shaded portion = Area of rectangle - Area of ∆BCE - Area of ∆FDE
= 180-(40+30)
= 180-70
= 110cm²
ii). In the given figure,
ABCD Is a square whose each side = 20cm
E And F are mid points of AB and AD respectively.
EC and FC are joined
Area of square ABCD = (Side)² = (20)² = 400cm²
Area of ∆EBC = 1/2×EB×BC
= 1/2×10×20 = 100cm²
Area of ∆FD2 = 1/2×10×20 = 100cm²
Area of ∆AEF = 1/2×10×10 = 50cm²
Area of shaded portion =
400-(100+100+50)cm²
400-250
= 150cm²
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