Question

in the following figures , find the value of x​

Answer 1

IN THE GIVEN FIGURE, WE HAVE,

BD=CD

LCBD=LDCB=27°

IN TRIANGLE BCD,

LCBD+LDCB+LBDC=180°

(ANGLE SUM PROPERTY OF A TRIANGLE )

or,27°+27°+LBDC=180°

or,54°LBDC=180°

or,LBDC=180°-54°

or,LBDC=126°

NOW,ADB IS A STRAIGHT LINE,WE GET

or,LADC +LBDC=180°

or,LADC=180°-126°

or,LADC=54°

ALSO, AC=DC

SO,LADC=LDAC=54°

IN TRIANGLE ACD,WE HAVE

LADC+LDAC+LACD=180°

(ANGLE SUM PROPERTY OF A TRIANGLE )

or,54°+54°+x°=180°

or,x°=180°-108°

or,x°=72°

THEREFORE, LACD=X°=72°

HOPE IT HELPS YOU ☺.

Answer 2

Answer:

Here is your answer

X=72°

Step-by-step explanation:

Hope it helps you