Question

In the following figures find thebvalue of x

Answer 1

Step-by-step explanation:

(i)

since AB=AC

therefore angle B=angle C - - -1

angle(A+B+C) =180°[angle sum property]

50°+2B=180°[from 1 B=C]

B=180°-50°/2

B=65°

now,

angle(A+B)=x°[exterior angle property]

50°+65°=115°=x°

(ii)

since PR=RS

therefore angle RPS=angle S

angle RPS= 30°

angle(RPS+S+PRS)=180°[angle sum property]

30°+30°+PRS=180°

PRS=180°-60°=120°

angle PRS=angleRPQ+angle Q[ exterior angle property]

120°=52°+x°

x°=120°-52°

x°=68°