Question

in the following figures show that angle bad and angle bcd​

Answer 1

Hey mate...

here is your answer ....

Given : ∆BAD and ∆BCD

such that AB=BC, AD =DC and angle A =angle C

Now , According to the question:

In ∆BAD and ∆BCD

BA=BC (given)

angle A =angle C(given)

AD=CD (given)

hence, ∆BAD~∆BCD

by SAS (side-angle-side)

★Hope it will be helpful for you★

Answer 2

Answer:

In ∆ABD and ∆BDC

<ABD=<BDC ( Each 90° )

<ABD=<BDC ( parallel to each other )

<AD=<CD ( Are Tangent )

hence, ∆ABD=∆BDC by AAA similarity

hence proved

hope it's helpful to you!!!!!