Question

In the following find the centre and radius of the circles: $x^{2} +x^{2} -8x+10y-12=0$

Answer 1

here is answer take the following step( s) into consideration !!

center is => ( -g , -f ) = (4 , -5 )

radius => ✓ g ² + f²- c

so
r => √ 16 +25 +12


r = √ 53

hope it help you !!

thanks !!

Answer 2

Answer:

centre of given circle is ( 4,-5)

Radius √16+25+12=√53 units

Step-by-step explanation:

The given equation should be like that x²+y²-8x+10y-12=0

We know that the standard equation of the circle is

x²+y²+2gx+2fy+c=0

where (-g,-f) are center of circle

and √(g²+f²-c) is radius

x²+y²-8x+10y-12=0

2gx = -8x

g = -4

2fy=10y

f= 5

So,centre of given circle is ( 4,-5)

Radius √16+25+12=√53 units