Math, asked by tanveer5629, 7 months ago

In the following, find the value of a;
(i) 4x^2 + ax + 9 = (2x + 3)^2​

Answers

Answered by LakR
1

Answer:

Follow the following steps:

Step-by-step explanation:

4x^2+ax+9=(2x+3)^2

4x^2+ax+9=4x^2+12x+9

4x^2-4x^2+9-9+ax=12x

ax=12x

a=12

Hope it helps you.

Answered by amishkvsjmp
0

 {4x}^{2}  + ax + 9 =  ({2x + 3})^{2}

Solving from RHS

( {2x + 3})^{2}  =  {4x}^{2}  + 9 + 12x

 {4x}^{2}  + ax + 9 =  {4x}^{2}  + 9 + 12x \\  {4x}^{2}  -   {4x}^{2}   + 9 - 9 + ax = 12x \\ ax = 12x \\ a = 12

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