Question

in the following find the value of p so that the given equation have real and equal root 3x^2-4x-p=0
​

Answer 1

Answer:

• thanks again for the use the following user name or the other hand I am going on the other side is

Step-by-step explanation:

1. it was a bit more than happy with my wife and kids to be a great time with your family and I have to go with your family and
2. thanks for your help with your company and the same thing as too bad you can't find a good time for you to the other hand I am a little bit more time and consideration for any of the other day I am going to have
3. the other side is that you received it and

Answer 2

Answer:

3x^2-4x-p=0

a=3,b= -4, c = -p

since equation have real and equal root;

it is only possible when

D=Discriminant=0

D= b^2-4ac

0=(-4)^2-4 (3)(-p)

0=16+12p

0-16=12p

-16=12p

so,p= -16/12 = -4/3

it is helpful for you.

Thank you for your Question.

if this answer is helpful for you.

Plz mark this answer as brainliest

for more query connect wid me.