Biology, asked by ponnus7, 3 months ago

In the following food chain, 20J of energy was available to the peacock. How much energy would have been present in the plants?

Plant------Rat------Snakes---- peacock.​

Answers

Answered by Anonymous
5

Answer:

The ten percent law is applicable to this food chain as well which is the transfer of energy from one trophic level to the next.

According to this law, during one transfer of energy from organic food from one trophic level to the next, only about ten percent of the energy from the organic matter is stored as flesh. The remaining is lost during transfer, broken down in respiration or lost to incomplete digestion by higher trophic levels.

In this food chain, the plant absorbs 10% of solar energy and is mentioned here, that absorbs 20 J of energy. Only 10% from this 20J is available for the next level, So, the mice will have (10% of 20J) 2J of energy available. Now, from 10% from this 2J will be available to the next trophic level (0.2J) and finally, the peacock will get 10% of this 0.2J of energy which is 0.02 J.

20Jplant→2Jmice→0.2Jsnake→0.02Jpeacock

Hence, the correct answer is '0.02 J'.

Answered by ahmadfardeen571
0

Answer:

0.02J

Explanation:

According to this law, only around 10 percent of the energy from organic food is stored as meat throughout one transfer of energy from one trophic level to the next. The rest is lost during transfer, respiration, or incomplete digestion at higher trophic levels.

Primary carnivores eat herbivores. Only ten percent of herbivore output is used to boost primary carnivore productivity. The rest is used up in digestion, respiration, body heat maintenance, and other functions. Similarly, higher carnivores can only maintain 10% of the energy found in primary carnivores. Lindeman proposed the 10% law, which is what it's called. As a result, if a plant captures 20 J of energy, mice will have 2 J, snake will have 0.2 J, and peacock will have 0.02 J.

plant → mice → snake → peacock

20J       2J        0.2J         0.02j

#SPJ3

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