Question

In the following network, the current flowing through 15 ohm resistance is

a. 0.8A
b. 1.0A
c. 1.2A
d. 1.4A

​

Answer 1

since 15/3 = 20/5

it is a balanced Wheatstone's bridge..

current through 15 ohm resistor =

ir2/r1+r2

=2.1(24)/42

=1.2 amp

hope it helps u....

Answer 2

Given :

The network of resistance .

To Find :

The current flowing through 15 ohm resistance .

Solution :

To answer this question one should know about balanced Wheatstone bridge.

So , it is a balanced wheatstone bridge .

Therefore , no current will flow through BD .

So , it can be removed .

Therefore , net resistance is given by :

$\dfrac{1}{R_{eq}}=\dfrac{1}{15+3}+\dfrac{1}{20+4}\\\\\dfrac{1}{R_{eq}}=\dfrac{1}{18}+\dfrac{1}{24}\\\\\dfrac{1}{R_{eq}}=10.28\ ohms$

Therefore , current through 15 ohms resistance is given by :

$I=\dfrac{24}{18+24}\times 2.1\\\\I=1.2\ A$

Therefore , option ( c ) is correct .

Learn More :

Wheatstone Bridge

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