Question

In the following one of the trigonomretric rarios is given.Find that values of all other trigonometric ratios:Tan thitha=√3.

Answer 1

tan@=√3

cot@ = 1/√3

cosec²x-cot²x = 1

cosec²x = 1+(1/√3)² = 1+ 1/3 = 3+1/3 = 4/3

cosec²x= 4/3

cosecx = 2/√3

sinx = 1/cosecx = √3/2

sin²+cos²x = 1

(√3/2)² +cos²x = 1

cos²x = 1- 3/4 = 4-3/4 = 1/4

cosx = 1/2

secx = 1/cosx = 2