In the following options, three out of the four are same in a certain way to form a group. Find the odd one. (A) 27 (B) 64 (C) 15 (D) 50
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Answered by
2
Answer:27
Step-by-step explanation:
27-1=26(not divisible by 7)
64-1=63(divisible by 7)
15-1=14(divisible by 7)
50-1=49(divisible by 7)
Answered by
0
Solution :-
Logic :- (Number - 1) ÷ 7 = An integer .
Explanation :-
checking all given options we get,
(A) 27
→ (27 - 1) ÷ 7
→ 26 ÷ 7
→ 3.71 ≠ Not an integer .
(B) 64
→ (64 - 1) ÷ 7
→ 63 ÷ 7
→ 9 = An integer .
(C) 15
→ (15 - 1) ÷ 7
→ 14 ÷ 7
→ 2 = An integer .
(D) 50
→ (50 - 1) ÷ 7
→ 49 ÷ 7
→ 7 = An integer .
therefore, (A) 27 is the odd one in the group .
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