Math, asked by koleyankita538, 1 month ago

In the following options, three out of the four are same in a certain way to form a group. Find the odd one. (A) 27 (B) 64 (C) 15 (D) 50​

Answers

Answered by bobwali1210
2

Answer:27

Step-by-step explanation:

27-1=26(not divisible by 7)

64-1=63(divisible by 7)

15-1=14(divisible by 7)

50-1=49(divisible by 7)

Answered by RvChaudharY50
0

Solution :-

Logic :- (Number - 1) ÷ 7 = An integer .

Explanation :-

checking all given options we get,

(A) 27

→ (27 - 1) ÷ 7

→ 26 ÷ 7

→ 3.71 ≠ Not an integer .

(B) 64

→ (64 - 1) ÷ 7

→ 63 ÷ 7

→ 9 = An integer .

(C) 15

→ (15 - 1) ÷ 7

→ 14 ÷ 7

→ 2 = An integer .

(D) 50

→ (50 - 1) ÷ 7

→ 49 ÷ 7

→ 7 = An integer .

therefore, (A) 27 is the odd one in the group .

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