in the following parallelogram find the value of x
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ABCD is a parallelogram, with diagonals AC and BD intersect at point O.
⇒ ∠A+∠B=180
o
[ Sum of adjacent angles are supplementary in parallel ]
⇒ 110
o
+(40
o
+x)=180
o
⇒ 150
o
+x=180
o
⇒ x=30
o
In △OBC,
⇒ ∠OBC+∠BCO+∠COB=180
o
⇒ x+50
o
+y=180
o
⇒ 30
o
+50
o
+y=180
o
⇒ 80
o
+y=180
o
∴ y=100
o
∴ x=30
o
,y=100
o
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