Question

In the following parallelograms, find the measures of the angles marked as x, y, z.​

Answer 1

Answer:

In parallelogram ABCD,

angle DAB+angle ABC=180°(co-interior angle)

100°+y=180°

y=180°-100°

y=80°

angle ABC=angle ADC(opposite angle parallelogram are equal)

y=angle ADC

angle ADC=80°

In parallelogram EFGH,

angle HGF+angle GFE=180°(co-interior angle)

70°+z=180°

z=180°-70°

z=110°

angle FGH=angle FEH(opposite angles of parallelogram are equal)

angle FEH=70°

Now,

In triangle ODE,

angle OED+angle EDO+angle EOD=180°

70°+80°+x=180°

150°+x=180°

x=180°-150°

x=30°

x=30°

y=80°

z=70°

Hope it's help u!!