Question

in the following pic. AB is parallel to CD.FIND the measure of angle 2​

Answer 1

ANSWER:

60°

Step-by-step explanation:

angle 1 + angle DCE = 180° ( consecutive angles)

angle 1 + 75° = 180 °

angle 1 = 180-75 = 105°

angle BE2 = angle 1 ( Vertically.

Opposite Angles )

=> angel BE2 = 105°

now in triangle BE2

15° + 105° + angle 2 = 180°

=> angle 2 = 180 - 15 - 105

=> angle 2 = 60°

Answer 2

Answer:

60°

Step-by-step explanation:

mark point on ∠2 as G.

AB║CD

so, ∠BEC=∠DEC=75°  (Alternate interior angles)

∠BEG=∠1=180°-75°=105°

Given,

∠GBE=15°

So, in ΔBEG,

∠BEG+∠BGE+∠GBE=180°

=>105°+∠2+15°=180°

=>∠2+120°=180°

=>∠2=180°-120°=60°

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