Question

In the following potentiometer, circuit AB is a uniform wire of length 1 m and resistance 10 Ω. Calculate the potential gradient along the wire and balance length AO(l).

Answer 1

Hello buddy,

● Answer -
x = 37.5 cm

● Explaination -
# Given -
R = 15 ohm
R' = 10 ohm
E = 2 V

# Solution -
Voltage across wire is calculated by -
V = ER' / (R+R')
V = 2 × 10 / (15 + 10)
V = 0.8 V

Potential gradient across wire is calculated as -
P.G. = V / l
P.G. = 0.8 / 1
P.G. = 0.8 V/m

Voltage across segment AO -
V' = 0.3 × 1.5 / (1.2+0.3)
V' = 0.3 V

Balance length AO is given by -
x = V' / P.G.
x = 0.3 / 0.8
x = 0.375 m
x = 37.5 cm

Therefore, potential gradient is 0.8 V/m and balance length AO is 37.5 cm.

Hope this helps you...

Answer 2

Answer:

37.5cm

Explanation:

current through 0.3ohm. =1.5/ 1.2+0.3

=1A

.

potential difference across 0.3ohm=1×0.3

=0.3V

.across length AO, , V=0.3 ,Vis to be balanced.

let L be the length AO,then

= 0.3=0.008×L

= L= 0.3/0.008

= L= 37.5cm