Question

In the following Problems each letter stands for a specific digit find the digits to mark the problem correct
3 A
× A
= 2BA​

Answer 1

Answer:

in the given problem,the the multiplication of A with A itself gives a number whose ones digit is A again. This happens only when a=1,5,6

if a =1 , then the multiplication will be 31*1 =31 .

However, here the tens digit is given as B and hundred digit is 2, therefore, a is not equal to 1

similarly if a is equal to 5 then the multiplication will be 35*5= 175 .However, here the tens digit is given as B and hundred digit is 2, therefore a is not equal to 5 .

now , if a=6 then the multiplication will be 36*6 = 216 .However, here the tens digit is given as B and hundred digit is 2, therefore,a =6 and b= 1 .

hence , the letter a= 6 and b= 1

Step-by-step explanation:

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