In the following prove that:
(i) (x + 3) is a factor of x^3+ 3x^2 - 4x - 12.
Hence, factorise the expression fully.
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Answered by
2
Answer:
x+3 is a factor
Therefore x+3=0
x= -3
P(x)=x³+3x²-4x-12
P(-3)=(-3)³+3(-3)²-4(-3)-12
P(-3)=-27+3×9+12-12
P(-3)=-27+27+12-12
P(-3)=0
Therefore remainder is 0
Therefore (x+3) is a factor of x³+3x²-4x-12
Answered by
16
Answer:
Using Factor theorem:--
-27+27+12-12=0
posted long division proof also
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