Question

In the following ray diagram, the given lens has a radius of curvature of 20cm. The object of height 1.5cm is kept at a distance of 5cm from the lens. The height of the image is

Answer 1

Answer:

Image Height is 3 cm

Explanation:

R = 2

f = 10

u = -5 (Object Distance)

h = 1.5 (Object Height)

v = ?? (Image Distance)

Use Lens formula

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$

Magnification formula

$\frac{height \: of \: image}{height \: of \: object} = \frac{image \: distance}{object \: distance}$