Question

In the following reaction, identify the salt formed NH4OH (aq) + H2SO4 (aq) → _____ + 2H2O (l)
Options are:
a. NH4NO3
b. (NH4)2SO4
c. (NH4)3PO4
d. (NH4) 2S​

Answer 1

Answer:

The product will be (NH₄)₂SO₄.

The balanced equation can be written as

2NH₄OH(aq) + H₂SO₄(aq) --> (NH₄)₂SO₄(aq) + 2 H₂0(l)

The ammonium hydroxide reacts with sulphuric acid. This is further broken down into positive and negative salts.

The cross-reaction will happen.

The oppositely charged salts of both the reactant will combine with each other.

This will result in the new product formation.

The product formed will be Ammonium tetraoxosulphate and water.

This product and reactants then come to an equilibrium state.

To attain this state they are always balanced.

Balancing any equation also preserved the Dalton's laws.

Here, when the equation is balanced, we get twice of ammonium hydroxide reacting with sulphuric acid to give ammoium tetraoxsulphate and twice of water.

The balanced equation looks like this:
2NH₄OH(aq) + H₂SO₄(aq) --> (NH₄)₂SO₄(aq) + 2 H₂0(l)

Here, each element is balanced on both the sides.

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Answer 2

Answer: b. (NH4)2SO4 is the salt formed in the reaction between NH4OH (aq) and H2SO4 (aq).

Step-by-step explanation:

Identify the strong acid and strong base in the reaction: H2SO4 (aq) is a strong acid, and NH4OH (aq) is a strong base.

Write out the ionic equations for the strong acid and strong base:

                    H2SO4 (aq) -> H+ (aq) + SO4^2- (aq)

                    NH4OH (aq) -> NH4+ (aq) + OH- (aq)

Combine the ionic equations to form the neutralization reaction:

      H+ (aq) + OH- (aq) + NH4+ (aq) + SO4^2- (aq) -> ________ + 2H2O (l)

Use the rules of ionic equations to balance the charges on both sides of the reaction:

                NH4+ (aq) + SO4^2- (aq) -> (NH4)2SO4 (s) + 2H2O (l)

The salt formed in the reaction is (NH4)2SO4.

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