Question

.In the following reaction if 10 gram of Hydrogen reacts with Nitrogen what will be the volume of Ammonia at STP.

Answer 1

Here is your answer.

Answer:

So, 1 gram of hydrogen will have 34/6 gran of NH3. Hence, 10 gram of hydrogen will have (34/6)*10 = 56.6 gram of ammonia. So, moles of ammonia will be 56.6/17 which will be 3.3 moles so the volume of ammonia is 3.3*22.4 litres = 74.5 litre of volume.

If you like it you can follow me or mark it brainliest.

Answer 2

Answer:

74.67 litres

Explanation:

N2 + 3H2 ----> 2NH3

10g h2

n=given weight/molecular weight

10/2=5mol

Produced moles of NH3 = 2/3×5=10/3

Volume of NH3 at STP = 10/3×22.4 = 74.67 litres

hope you understand ❤️