IN THE FOLLOWING REACTION IT IS FOUND THAT 3.4 g OF AgNo3 combines with 1.5g OF NaCl .2.8g OF AgCl is PRECIPITATED . APPLY LAW OF CONSERVATION OF MASS AND CALCULATE THE MASS OF NaNo3 .
AgNo3 + NaCl -------> AgCl + NaNo3
Answers
Answer :-
Required mass of NaNO₃ is 2.1 grams .
Explanation :-
We have :-
→ Mass of AgNO₃ = 3.4 g
→ Mass of NaCl = 1.5 g
→ Mass of AgCl = 2.8 g
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AgNO₃ + NaCl → AgCl + NaNO₃
In this chemical equation :-
• Silver Nitrate [AgNO₃] and Sodium Chloride [NaCl] are reactants.
• Silver chloride [AgCl] and NaNO₃ [Sodium Nitrate] are products.
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According to Law of Conservation of mass :-
Mass of reactants = Mass of products
Let the required mass of NaNO₃ be 'x grams' .
⇒ 3.4 + 1.5 = 2.8 + x
⇒ 4.9 = 2.8 + x
⇒ x = 4.9 - 2.8
⇒ x = 2.1 g
Answer:
Given :-
Mass of AgNo3 = 3.4 gram
Mass of NaCI = 1.5 gram
Mass of AgCI = 2.8 gram
To Find :-
Mass of NaNo3
Solution :-
By using the law of conservation of mass
AgNo3 + NaCI = AgCI + NaNo3
3.4 + 1.5 = 2.8 + NaNo3
(3.4 + 1.5) - 2.8 = NaNo3
4.9 - 2.8 = NaNo3
2.1 = NaNo3
Mass of NaNo3 is 2.1 grams