Question

In the
following reaction
neaction XA -----> YB

log (-d/dt(A)] = log [d/dt[B] + 0.3

where are sign indicate rate
rate of dissapear
of rectant than X:Y is .​

Answer 1

Answer:

Explanation:t will be 2:1 as we know for a simple chemical reaction

average rate of dissapearance= average rate of apperance

A → B

-dA/dT= dB/dT  

So for this reaction, (-dA/dT)/ x = (dB/dT)/y                                          ….(i)

We can write 0.3 as log 2 (Approx)  

then applying property of log... log a + log b= log ab

we get log(-dA/dT)= log 2(dB/dT)

taking antilog both sides and dividing by 2 and compare with (i)

x=2, y=1 hence x:y =2:1