In the
following reaction
neaction XA -----> YB
log (-d/dt(A)] = log [d/dt[B] + 0.3
where are sign indicate rate
rate of dissapear
of rectant than X:Y is .
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Answer:
Explanation:t will be 2:1 as we know for a simple chemical reaction
average rate of dissapearance= average rate of apperance
A → B
-dA/dT= dB/dT
So for this reaction, (-dA/dT)/ x = (dB/dT)/y ….(i)
We can write 0.3 as log 2 (Approx)
then applying property of log... log a + log b= log ab
we get log(-dA/dT)= log 2(dB/dT)
taking antilog both sides and dividing by 2 and compare with (i)
x=2, y=1 hence x:y =2:1
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