In the following reaction3fe+4h20--fe3+4h2if the atomic weight of iron is 56,then is equivalent weight will be
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Fe3O4
let oxidation state of fe is x
3x -8 = 0
3x = 8
x= 8/3
So n factor = 8/3
Equivalent weight = atomic mass/n factor
= 56/ 8/3 = 56× 3/8 = 21
Explanation:
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