In the following sequence of reactions, how many hydroxyl group (-OH) are present product(D)? COOH Oso, HIOA LIAIH. (A) (B) (C) - (D) (excess) COOH +
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Answer:
acetoxime
The product 'C' in the following sequence of chemical reaction is Acetoxime.
CH
3
COOH
Ca(OH)
2
(A)
(CH
3
COO)
2
Ca
Δ
(B)
C
H
3
COCH
3
NH
2
OH
Acetoxime
CH
3
C
∣
H
3
C
=N−OH
Acetic acid reacts with calcium hydroxide to give calcium acetate.
Calcium acetate on dry distillation gives acetone.
Acetone undergoes condensation reaction with hydroxylamine to form acetoxime.
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