Question

In the following situation does the list of number involved make on AP ? Give reason.
The amount of air present in a cylinder when a vacuum bump removes 1/6 of the air remaining in the cylinder at a time
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Answer 1

Answer:

no

it is not an arithmetic progression

Step-by-step explanation:

Let a be the amount of air initially Amount of air remaining after 1st pump =a –(a/4)=3a/4

Amount of air remaining after 2nd  pump= (3a/4) – (1/4)(3a/4)=9a/16

Amount of air remaining after 3rd  pump= (9a/16) – (1/4)(9a/16)=27a/64

So the series is like

a,3a/4,9a/4,27a/64……..

Difference Ist and second term=-a/4

Difference between Second and Third term= -3a/16

So difference is not constant

So it is not Arithmetic Progression

Step-by-step explanation:

Answer 2

Answer:

It is not an ap

Step-by-step explanation:

because it does not add a fix number to the preceding number

Hope this will help you ☺️

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