In the following state whether A=B or not (iv) x:x is a multiple of 10),B= ( 10,15,20,25,30.......)
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Step-by-step explanation:
A={a,b,c,d};B={d,c,b,a}
The order in which the elements of a set are listed is not significant.
∴A=B
(ii) A={4,8,12,16};B={8,4,16,18}
It can be seen that 12ϵA but 12
ϵB.
∴A
=B
(iii) A={2,4,6,8,10}
B={x:x is a positive even integer and x≤10}
={2,4,6,8,10}
∴A=B
(iv) A={x:x is a multiple of 10}
So, A={10,20,30,40....}
B={10,15,20,25,30....}
It can be seen that 15ϵB but 15
ϵA.
∴A
=B
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