Question

in the following system of linear equation determine whether a system has a unique solution, no solution or infinitely many solution in case there is unique solution find it 3x-5y=20, 7x+2y=17​

Answer 1

Step-by-step explanation:

case 1

for 3x + 5y = 20,

let x = 1, we have

3(1)+5y = 20

3+ 5y = 20

5y= 20-3

5y = 17

y = 17/5

therefore, when x = 1 y = 17/5

now let x = 2 in same equation,we get;

3 (2) + 5y = 20

6 + 5y = 20

5y = 20-6

5y= 14

y=14/5

therefore, when x= 2,y= 14/5

case 2...

7x+2y= 17

putting y = 1; we have,

7x +2(1)= 17

7x + 2= 17

7x = 17-2

7x= 15

x= 15/2

therefore, when y =1, x= 15/2

putting , y = 3; we have,

7x + 2(3) = 17

7x +6 = 17

7x= 17-6

7x= 11

x= 11/17

therefore, when y= 3, x= 11/7

from above solutions, we conclude that a linear equation in one variable can have infinitt many solutions based on what values of x and y.

I hope this helps!