In the following table, six elements A, B, C, D, E and F (here letters are not the usual symbols of the elements) of the modern Periodic Table with atomic numbers 3 to 18 are given:
(a) Which of these is (i) a noble gas, (ii) a halogen?
(b) If B combines with F, what would be the formula of the compound formed?
(c) Write the electronic configurations of C and E.
Answers
Answer:
a)
i) none of it is a noble gas
ii)none
b) BeO
c) C = 2 , 3
E = 2 , 5
{ NOTE: I have taken it as atomic numbers from 3 to 8}
IF THIS IS THE CORRECT ANSWER PLS MARK MY ANS AS BRAINLIEST:)
AND IT WAS NICE HELPING U!
Periodic Table
Explanation:
The image is missing in the question to show the options. Please find the attached picture for the image. The answer is with respect to the attached picture only.
(a)
(i) Elements of Group 18 are noble gases - Neon (Ne) with atomic number 10 and Argon (Ar) with atomic number 18.
(ii) Elements of Group 17 are halogens - Fluorine (F) with atomic number 9 and Chlorine (Cl) with atomic number 17.
(b) B with atomic number 11 has 1 valence electron. The element is Sodium (Na). F with atomic number 17 has 7 valence electrons. The element is Chlorine. Compound formed by these two elements will be NaCl.
(c) Electronic configuration of E8 is Oxygen (O): 2, 6.
Electronic configuration of C12 is Magnesium (Mg): 2, 8, 2.