in the following the comes for men
A 2 AS = 12:"2
B:V2=U*2=2AS
CAS =V*2- U"272
DEB AND C BOTH
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graph for derivation
we know : displacement = area under the velocity time graph .
S= area of trapezium ACEF
S= 1/2 ( b¹ + b² ) h
s= 1/2 ( AF+CE )FE
S= 1/2 ( U+ V) T
We know -v= u+ at
v-u/a= t
now 2 in 1
S= 1/2( v+u) (v-u)
2as= ( v+u) (v-u)
2as=v²-u²
[v² - u2 = 2as]
hope it will help u
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