In the following triangle ABC, B = 70, BDE 110, BC = 5cm and AE =CE= 3cm. Then the length of DE is
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Answer:
The given information is shown in the attached diagram.
DE∣∣BC
⟹∠ADE=∠ABC Corresponding angles
∠AED=∠ACB Corresponding angles
∠A is common to both the triangles.
∴ΔADE∼ΔABC by AAA similarity
⟹
AD
AB
=
AE
AC
AD
AB
−1=
AE
AC
−1
AD
BD
=
AE
CE
EC=1×
1.5
3
=2 cm
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