in the following triangle , ST parallel to PQR , RS is equal to
options
a.PT/TR
b.PS/TR
c.PT/SQ
d.PT/SR
Answers
Answered by
8
Answer:
Sorry
Step-by-step explanation:
I could not understand
Answered by
2
Step-by-step explanation:
Answer
Given that:
QP=8cm,PR=6cm and SR=3cm
(I) In △PQR and △SPR
∠PRQ=∠SRP (Common angle)
∠QPR=∠PSR (Given that)
∠PQR=∠PSR (Properties of triangle )
∴△PQR∼△SPR (By AAA)
(II)
SP
PQ
=
PR
QR
=
SR
PR
(Properties of similar triangles)
⇒
SP
8cm
=
3cm
6cm
⇒SP=4cm and
⇒
6cm
QR
=
3cm
6cm
⇒QR=12cm
(III)
ar(△SPR)
ar(△PQR)
=
SP
2
PQ
2
=
4
2
8
2
Similar questions