Chemistry, asked by lickeay, 6 months ago

In the formation of BF3, molecule,Boron
atom undergoes

A) sp2 -hybridisation
B) sp -hybridisation
C) sp3 -hybridisation
D) dsp²? -hybridisation​

Answers

Answered by laxmidevasani983
1

BF3 has a boron atom with three outer-shell electrons in its ground state and three fluorine atoms containing seven outer electrons. ... In short, Boron needs 3 hybridized orbitals to make bonds with 3 atoms of F where the 2pz orbitals get overlapped with these hybridized sp2 orbitals and bonds are formed.

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Answered by Anonymous
5

In the formation of BF3, molecule,Boron

atom undergoes sp²hybridisation.

BF3 has a boron atom with three outer-shell electrons in its ground state and three fluorine atoms containing seven outer electrons. ... In short, Boron needs 3 hybridized orbitals to make bonds with 3 atoms of F where the 2pz orbitals get overlapped with these hybridized sp2 orbitals and bonds are formed.

Hence, option A) is the correct option

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