In the formation of compound between two atoms A and B. A losses two electron B gain one electrons.i) what is the nature of bond A and B.ii) Suggest the formula of the compound formed between A and B.iii) On similar line explain the formation Mgcl2
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Heya friend!!
A loses Two electrons, so it is a metal and forms a positively charged ion.
B gains an electron, so it is a non metal and forms negatively charged ion.
Now, a bond between a metal and non metal is always ionic.
I) So nature of bond is ionic or electrovalent.
ii) Since A loses 2 electrons, its valency is +2 and valency of B is -1 since it gains one electron. On interchanging them, we get the formula, which is AB2.
iii) Mg is a metal which has two electrons in the outermost shell..so to form a cation, it needs to donate the two electrons to chlorine, which has one electron short of octet. Thus, The two donated electrons of magnesium and accepted by two chlorine atoms (one each).
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A loses Two electrons, so it is a metal and forms a positively charged ion.
B gains an electron, so it is a non metal and forms negatively charged ion.
Now, a bond between a metal and non metal is always ionic.
I) So nature of bond is ionic or electrovalent.
ii) Since A loses 2 electrons, its valency is +2 and valency of B is -1 since it gains one electron. On interchanging them, we get the formula, which is AB2.
iii) Mg is a metal which has two electrons in the outermost shell..so to form a cation, it needs to donate the two electrons to chlorine, which has one electron short of octet. Thus, The two donated electrons of magnesium and accepted by two chlorine atoms (one each).
Thanks..
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