Question

in the formation of compound between two atoms A and B, A.loses two electrons and B gains one electron 1)what is the nature of the bond formed between A and B 2)write down the formula of the ions formed from A and B 3)draw the electron dot structure for ions in the above compound you mentioned​

Answer 1

A loses Two electrons, so it is a metal and forms a positively charged ion.

B gains an electron, so it is a non metal and forms negatively charged ion.

Now, a bond between a metal and non metal is always ionic.

I) So nature of bond is ionic or electrovalent.

ii) Since A loses 2 electrons, its valency is +2 and valency of B is -1 since it gains one electron. On interchanging them, we get the formula, which is AB2.

iii) Mg is a metal which has two electrons in the outermost shell..so to form a cation, it needs to donate the two electrons to chlorine, which has one electron short of octet. Thus, The two donated electrons of magnesium and accepted by two chlorine atoms (one each).

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Answer 2

1) Ionic bond

2)A(B)2 (2 is subscript)

3)answer. given in the attachment.

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