in the formation of homo diatomic neutral molecule if 'N' atomic orbitals combine then the total number of bonding molecular orbitals formed
1)2N
2)N
3)N/2
4)N/4
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molecule form by using both of the atomic orbit from that specics. it will form total same no of orbital but half is bonding and half is anti bonding. so, the answer is N/2..
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