Question

In the formation of NO; 2N2O(g) + O2(g) → 4NO(g) , ΔH >0, list out the conditions for maximum yield

of NO ?​

Answer 1

Answer:

Determine ∆G at 298 K and determine if this reaction is ... Delta G°= Delta H°-T DeltaS°=0 ... ClNO2 (g) + NO (g) --> NO2 (g) + ClNO (g).

Answer 2

Answer

⇒we will use Le chateleir's principle to find maximum yielding conditions, which states that

'when a system experiences a disturbance (such as concentration, temperature, or pressure changes), it will respond to restore a new equilibrium state.'

⇒Here, we have to increase the yield of NO. i.e, we have to increase the rate of forward reaction.

⇒According to Le chateleirs principle, to increase forward reaction, we can,

☆Add more amount of N2O and O2

(increasing concentration of any reactant will disturb the equilibrium and system will try to decrease the concentration of the reactant by proceeding in forward direction, therefore,More NO will be formed)

☆Remove NO formed.

(decreasing concentration of the product formed will also disturb the equilibrium and system will try to increase the amount of product by favouring forward direction.)

☆Increase the temperature.

(given,/\H is +ve, which means that it is an endothermic reaction and formation NO occurs by absorbing heat. So, If we increase the temperature, system will try to decrease it by increasing the rate of forward reaction.)

☆decrease the pressure.

(decreasing pressure favours reaction to the side having more number of moles. here, reaction side have 3 moles and product side have 4 moles of a substances so, to increase product, we will have to decrease the pressure.)

hope it helps ....!!!