Chemistry, asked by tapsrathod948, 11 months ago

In the formation of S02 by contact process;
2SO2 + O2 → 2SO3, the rate of reaction was measured as \frac{-d[O2]}{dt} =2.5 x 10^{-4} mol L^{-1} s^{-1} at.
The rate of formation of of S03 will be
(a) -5.0 × 10-4 mol L-1s-1
(b) -1.25 × 10-4 mol L-1s-1
(c) 3.75 × 10-4 mol L-1s-1
(d) 5.00 × 10-4 mol L-1s-1

Answers

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