Question

in the formation of which of the following compounds octet rule is not obeyed?
(a) NaCl (b) CaO (c) MgCl2 (D) BF3​

Answer 1

Option (D) is the correct one

In BF3, around boron there is only 6e- that means boron is e- deficient

Hope this is helpful to you...

Pls mark as brainliest...

Follow me and I'll follow back...

Answer 2

Answer is 4.

i. e BF3.

F

|

F --- B---F

BF3 have three bond , Therefore there are 3×2 electron.

Since B have only 6 electron and it have not completed octet and thereby it is electron deficient.

So answer is BF3.