Question

In the formula loga xy = logax + logay,
which of the following is true ?


1) x > 0, y > 0, a = 1
2) x < 0, y < 0, a = 1
3) a > 0, y > 0, x = 1
4) x > 0, y >0, a #1​

Answer 1

Answer:

Step-by-step explanation:

logaxy = m (let)

xy = a^m

if a= 1, then xy has to be 1

similarly x has to be 1 and y has to be 1

now, log11 has infinite solution since, 1 raised to any power is 1. hence, the formula will have no meaning.

so, for meaningful formula, a needs to be not equal to 1. hence option d