In the fourmula X=3YZ^(2), X and Z have dimensions of capacitance and magnetic induction respectivey. What are the dimensions of Y is MKSQ system?
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Answer:
answer : [M^-3 T^8 A^4 ]
Explanation:
In the formula, X = 3YZ² , X and Z have the dimensions of capacitance and magnetic induction.
we have to find dimension of Y in the mks system.
formula can be written as , Y = X/3Z²
from dimensional analysis,
or, dimension of Y = dimension of {X/3Z²}
= dimension of X/dimension of Z² [ as we know, numbers are dimensionless quantity so, 3 is dimensionless quantity.]
dimension of X = dimension of capacitance = [M-¹L-²T²Q²]
dimension of Z = dimension of magnetic induction = [MT-¹Q-¹]
so, dimension of Y = [M-¹L-²T²Q²]/[MT-¹Q-¹]²
= [M³ L-² T⁴ Q⁴ ]
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