Question

in the future,PQ,PR and AB are tangents PQ=14. a) find the length of PR? b) find the perimeter of∆PAB?​

Answer 1

Answer:

Step-by-step explanation:

In the given circle,

PQ=PR (Tangents from the external point P)

XB=BQ (Tangents from the external point B)

XC=CR (Tangents from the external point C)

Perimeter of △PCB is PC+CB+PB but CB=CX+XB,

Therefore, perimeter of △PCB is PC+CX+XB+PB but CX=CR and XB=BQ

Therefore, perimeter of △PCB is PC+CR+PB+BQ but PC+CR=PR and PB+BQ=PQ

Therefore, perimeter of △PCB is PR+PQ but PQ=PR=7 cm [As length of the tangents drawn from an external point are equal]

Hence, perimeter of △PCB is 7+7=14 cm.