Question

In the garden pea, orange pods (p) are recessive to green pods (P), and sensitivity to pea mosaic virus (mo) is recessive to resistance to the virus (Mo). A plant with orange pods and sensitivity to the virus was crossed to a true-breeding plant with green pods and resistance to the virus. The F1 plants were then test crossed two plants with orange pods and sensitivity to the virus. The following results were obtained: 204 orange pods, virus-sensitive; 202 green pods, virus-resistant; 203 orange pods, virus-resistant; 205 green pods, virus-sensitive
Question: Conduct a chi square analysis to see if these genes are linked.​

Answer 1

Answer:

The answer to the question is as under-

Explanation:

First of all, we will see the total number of observations.

We will find that , the total number of observation =400.

Multiplied by 1 60 and add 16536.39.

We have got P Is O. M. M. When we Crossed them with oh mm mm.

So the new meeting is therefore oh oh mm mm.

When crossed with lower case 00. M. M.

We get the expected phenotype ratio that is 1-1-1-1.

So, the total number of offspring is 400.

And ,therfore, the expected number of each phenotype = 100

we will look at tri squared , which is, the sum of the observation, subtracting the exponential squared over the exponential .

We will subtract the expected square dividing it  by the expected.

So, we get; 165 -100 Squared divided by 139 -100 Squared.

Taking away 100 at 36 then, taking away 100 squared divided by 100 at 1 60. Taking away 100 squared divided by 100.
That gives us 156.42 which gives us a p value that is less than not point not  one.

The observation  is significant  differentthan our expectation.

We will  move on to part C.

Here ,the map unit  was the percent recombination.

The two recumbent classes will be green. Therfore, the virus sensitive and the orange is thevirus resistant groups. And thus, finally in part D Therefore, distance between the two genes.

We have36 and 39 divided by 400, all  then multiplied by 100=18.8 emu So ,therefore the genes are 18.8 m. ap units apart.

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