in the give figure a right triangle abc is inscribed in a circle such that ac is the diameter ab is 24 cm bc is 10 cm find the area of shaded region
Answers
Answer:
BC²=AC²+AB²
=8²+6²
=64+36
=100
BC=10cm
Area of biggest semicircle= 1/2 * 3.14 * r²
=0.5*3.14*5*5
=0.5*78.5
=39.25 cm²
Area of 2nd Largest Semicircle = 0.5*3.14*r²
=0.5*3.14*3²
=0.5*3.14*9
=14.13 cm²
Area of smallest Semicircle = 0.5*3.14*r²
=0.5*3.14*4²
=0.5*3.14*16
=25.12 cm²
Area of Triangle = 1/2 *b*h
= 0.5*6*8
=24 cm²
Area of shaded region = (24+25.12+14.13) - 39.25
= 63.25-39.25
=24 cm²