In the given ∆ ABC, AD Perpendicular to BC and CE perpendicular to AB. Prove that: angle BDE = angle BAC.
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Step-by-step explanation:
In ΔABD and ΔCBE
AB=BC [given ]
∠ADB=∠CEB=90
o
[Perpendiculars]
∠B=∠B [common side ]
ΔABD≅ΔCBE [by SAS congruence ]
Also,
AD=CE [ cpct]
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